Exercises: Means - Answer Key

By Christopher van Hoecke and Max Margenot

https://www.quantopian.com/lectures/means

IMPORTANT NOTE:

This lecture corresponds to the Means lecture, which is part of the Quantopian lecture series. This homework expects you to rely heavily on the code presented in the corresponding lecture. Please copy and paste regularly from that lecture when starting to work on the problems, as trying to do them from scratch will likely be too difficult.

Part of the Quantopian Lecture Series:


Key Concepts

In [1]:
# Useful Functions
def mode(l):
    # Count the number of times each element appears in the list
    counts = {}
    for e in l:
        if e in counts:
            counts[e] += 1
        else:
            counts[e] = 1
            
    # Return the elements that appear the most times
    maxcount = 0
    modes = {}
    for (key, value) in counts.iteritems():
        if value > maxcount:
            maxcount = value
            modes = {key}
        elif value == maxcount:
            modes.add(key)
            
    if maxcount > 1 or len(l) == 1:
        return list(modes)
    return 'No mode'
In [2]:
# Useful Libraries
import scipy.stats as stats
import numpy as np

Data:

In [3]:
l=[]
for x in range(1,100):
    x=np.random.randint(1,100)
    l.append(x)

Exercise 1 : Arithmetic mean.

a. Mean of random data set.

Find the mean of the randomly generated data set l.

In [4]:
## Your code goes here       
print 'mean of l:', np.mean(l)
mean of l: 50.5656565657

b. Mean of returns

Find the mean of the returns of Iteris, Inc. (ITI) for 5 years.

In [5]:
price = get_pricing('ITI', fields='price', start_date='2005-01-01', end_date='2010-01-01')
returns = price.pct_change()[1:]

## Your code goes here.
print 'mean of ITI returns:', np.mean(returns)
mean of ITI returns: -8.33695292019e-05

Exercise 2 : Median

a. Median of random data set

Find the median of the randomly generated data set l.

In [6]:
## Your code goes here. 
print 'median of l:', np.median(l)    
median of l: 50.0

b. Median of the returns.

Find the median associated with the returns of Bank of America Corp. (BAC) for the last 5 year.

In [7]:
price = get_pricing('BAC', fields='open_price', start_date='2005-01-01', end_date='2010-01-01')
returns = price.pct_change()[1:]

## Your code goes here
print 'Median of BAC returns:', np.median(returns)
Median of BAC returns: -0.000409084894317

Exercise 3 : Mode

a. Mode of a random data set.

Find the mode of the random generated data set l.

In [8]:
## Your code goes here. 
print 'mode of l:', mode(l)
mode of l: [33, 36, 6, 97, 49, 20, 61]

b. Mode of the returns.

Find the mode associated witht the returns of Goldman Sachs Corp. (GS). Recall with returns, there may not be any values that appear more than once.

In [9]:
start = '2014-01-01'
end = '2015-01-01'
pricing = get_pricing('GS', fields='price', start_date=start, end_date=end)
returns = pricing.pct_change()[1:]
hist, bins = np.histogram(returns, 20)
maxfreq = max(hist)

print 'Mode of bins:', [(bins[i], bins[i+1]) for i, j in enumerate(hist) if j == maxfreq]
Mode of bins: [(-0.00010566806392644026, 0.0030766703077806379)]

Exercise 4 : Geometric mean

a. Geometric Mean of random data set.

Find the Geometric mean of the random generated data set.

In [10]:
## Your code goes here.
print 'Geometric mean of l:', stats.gmean(l) 
Geometric mean of l: 38.6117060197

b. Geometric Mean of returns.

Find the Geometric Mean of the price of Citi bank (C) for the last 5 years.

In [11]:
price = get_pricing('C', fields='open_price', start_date='2005-01-01', end_date='2010-01-01')
print 'Geometric mean of Citi:', stats.gmean(price) ## Your code goes here
Geometric mean of Citi: 21.5434707851

Exercise 5 : Harmonic mean.

a. Harmonic Mean of random data set.

Find the harmonic mean of the randomly generated data set l.

In [12]:
## Your code goes here.
print 'Harmonic mean of l:', stats.hmean(l)
Harmonic mean of l: 22.2574570043

b. Harmonic Mean of stock returns.

Find the Harmonic Mean of the financial ETF (XLF) over the last 2 years.

In [13]:
## Your code goes here.
print 'Harmonic mean of XLF:', stats.hmean(price)
Harmonic mean of XLF: 11.6044060787

Exercise 6 : Skewness and why it matters.

Skewness in a probability distribution is the measure of asymmetry. Negative skew has fewer low values and a longer left tail, whereas positive skew has fewer high values and a longer right tail. In asset pricing, skewness is an important information, naimly in risk assessment. Knowledge that the market has a 60% chance of going down and a 40% chance of going up apears helpfull but only if we know the market is obeying a normal distrubtuion. If we are told that the market will go up 2% but down 18%, we can see how skewness would give us better information.

Determine if the returns of SPY from 2010 to 2017 is positivly or negativly skewed. Recall a data set is positivly skewed if the mode is smaller than the median, which is smaller than the mean. A data set is negativly skewed in the event of the reverse (i.e: the mean is greater than the median, which is greater than the mode)

In [14]:
import matplotlib.pyplot as plt
# Collect Data.
price = get_pricing('SPY', fields='volume', start_date='2016-01-01', end_date='2017-01-01')
returns = price.pct_change()[1:]

# Calculate Mean, Median and Mode. 
mean = np.mean(returns)
median = np.median(returns)
mode = stats.mode(returns)[0][0]

print 'mean:', mean
print 'median:', median
print 'mode:', mode
print len(returns)

# Setting parameters and print skewness outcome. 
if mode < median < mean:
    print  'The returns are positivly skewed.'
if mean<median<mode: 
    print 'The returns are negativly skewed.'
if mean == median == mode:
    print 'There is no Skewness: the returns are symetricaly distributed'
mean: 0.0525053496783
median: -0.0460440753442
mode: -0.588427240485
251
The returns are positivly skewed.

We can clearly see positive skewing from the histogram of the returns. We see fewer higher values and a longer right tail. Plot the histograms of the returns now.

In [15]:
plt.hist(returns, bins = 50);
plt.xlabel('Returns');
plt.ylabel('Frequency');
plt.title('Histogram of Returns');

Congratulations on completing the answer key to the Means exercises!

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